3.3.59 \(\int x^2 (A+B x) (a+c x^2)^2 \, dx\)

Optimal. Leaf size=65 \[ \frac {1}{3} a^2 A x^3+\frac {1}{4} a^2 B x^4+\frac {2}{5} a A c x^5+\frac {1}{3} a B c x^6+\frac {1}{7} A c^2 x^7+\frac {1}{8} B c^2 x^8 \]

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Rubi [A]  time = 0.05, antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {766} \begin {gather*} \frac {1}{3} a^2 A x^3+\frac {1}{4} a^2 B x^4+\frac {2}{5} a A c x^5+\frac {1}{3} a B c x^6+\frac {1}{7} A c^2 x^7+\frac {1}{8} B c^2 x^8 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2*(A + B*x)*(a + c*x^2)^2,x]

[Out]

(a^2*A*x^3)/3 + (a^2*B*x^4)/4 + (2*a*A*c*x^5)/5 + (a*B*c*x^6)/3 + (A*c^2*x^7)/7 + (B*c^2*x^8)/8

Rule 766

Int[((e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(e*x
)^m*(f + g*x)*(a + c*x^2)^p, x], x] /; FreeQ[{a, c, e, f, g, m}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int x^2 (A+B x) \left (a+c x^2\right )^2 \, dx &=\int \left (a^2 A x^2+a^2 B x^3+2 a A c x^4+2 a B c x^5+A c^2 x^6+B c^2 x^7\right ) \, dx\\ &=\frac {1}{3} a^2 A x^3+\frac {1}{4} a^2 B x^4+\frac {2}{5} a A c x^5+\frac {1}{3} a B c x^6+\frac {1}{7} A c^2 x^7+\frac {1}{8} B c^2 x^8\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 65, normalized size = 1.00 \begin {gather*} \frac {1}{3} a^2 A x^3+\frac {1}{4} a^2 B x^4+\frac {2}{5} a A c x^5+\frac {1}{3} a B c x^6+\frac {1}{7} A c^2 x^7+\frac {1}{8} B c^2 x^8 \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2*(A + B*x)*(a + c*x^2)^2,x]

[Out]

(a^2*A*x^3)/3 + (a^2*B*x^4)/4 + (2*a*A*c*x^5)/5 + (a*B*c*x^6)/3 + (A*c^2*x^7)/7 + (B*c^2*x^8)/8

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^2 (A+B x) \left (a+c x^2\right )^2 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^2*(A + B*x)*(a + c*x^2)^2,x]

[Out]

IntegrateAlgebraic[x^2*(A + B*x)*(a + c*x^2)^2, x]

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fricas [A]  time = 0.35, size = 53, normalized size = 0.82 \begin {gather*} \frac {1}{8} x^{8} c^{2} B + \frac {1}{7} x^{7} c^{2} A + \frac {1}{3} x^{6} c a B + \frac {2}{5} x^{5} c a A + \frac {1}{4} x^{4} a^{2} B + \frac {1}{3} x^{3} a^{2} A \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(B*x+A)*(c*x^2+a)^2,x, algorithm="fricas")

[Out]

1/8*x^8*c^2*B + 1/7*x^7*c^2*A + 1/3*x^6*c*a*B + 2/5*x^5*c*a*A + 1/4*x^4*a^2*B + 1/3*x^3*a^2*A

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giac [A]  time = 0.18, size = 53, normalized size = 0.82 \begin {gather*} \frac {1}{8} \, B c^{2} x^{8} + \frac {1}{7} \, A c^{2} x^{7} + \frac {1}{3} \, B a c x^{6} + \frac {2}{5} \, A a c x^{5} + \frac {1}{4} \, B a^{2} x^{4} + \frac {1}{3} \, A a^{2} x^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(B*x+A)*(c*x^2+a)^2,x, algorithm="giac")

[Out]

1/8*B*c^2*x^8 + 1/7*A*c^2*x^7 + 1/3*B*a*c*x^6 + 2/5*A*a*c*x^5 + 1/4*B*a^2*x^4 + 1/3*A*a^2*x^3

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maple [A]  time = 0.04, size = 54, normalized size = 0.83 \begin {gather*} \frac {1}{8} B \,c^{2} x^{8}+\frac {1}{7} A \,c^{2} x^{7}+\frac {1}{3} B a c \,x^{6}+\frac {2}{5} A a c \,x^{5}+\frac {1}{4} B \,a^{2} x^{4}+\frac {1}{3} A \,a^{2} x^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(B*x+A)*(c*x^2+a)^2,x)

[Out]

1/3*A*a^2*x^3+1/4*B*a^2*x^4+2/5*a*A*c*x^5+1/3*a*B*c*x^6+1/7*A*c^2*x^7+1/8*B*c^2*x^8

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maxima [A]  time = 0.57, size = 53, normalized size = 0.82 \begin {gather*} \frac {1}{8} \, B c^{2} x^{8} + \frac {1}{7} \, A c^{2} x^{7} + \frac {1}{3} \, B a c x^{6} + \frac {2}{5} \, A a c x^{5} + \frac {1}{4} \, B a^{2} x^{4} + \frac {1}{3} \, A a^{2} x^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(B*x+A)*(c*x^2+a)^2,x, algorithm="maxima")

[Out]

1/8*B*c^2*x^8 + 1/7*A*c^2*x^7 + 1/3*B*a*c*x^6 + 2/5*A*a*c*x^5 + 1/4*B*a^2*x^4 + 1/3*A*a^2*x^3

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mupad [B]  time = 0.02, size = 53, normalized size = 0.82 \begin {gather*} \frac {B\,a^2\,x^4}{4}+\frac {A\,a^2\,x^3}{3}+\frac {B\,a\,c\,x^6}{3}+\frac {2\,A\,a\,c\,x^5}{5}+\frac {B\,c^2\,x^8}{8}+\frac {A\,c^2\,x^7}{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(a + c*x^2)^2*(A + B*x),x)

[Out]

(A*a^2*x^3)/3 + (B*a^2*x^4)/4 + (A*c^2*x^7)/7 + (B*c^2*x^8)/8 + (2*A*a*c*x^5)/5 + (B*a*c*x^6)/3

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sympy [A]  time = 0.08, size = 61, normalized size = 0.94 \begin {gather*} \frac {A a^{2} x^{3}}{3} + \frac {2 A a c x^{5}}{5} + \frac {A c^{2} x^{7}}{7} + \frac {B a^{2} x^{4}}{4} + \frac {B a c x^{6}}{3} + \frac {B c^{2} x^{8}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(B*x+A)*(c*x**2+a)**2,x)

[Out]

A*a**2*x**3/3 + 2*A*a*c*x**5/5 + A*c**2*x**7/7 + B*a**2*x**4/4 + B*a*c*x**6/3 + B*c**2*x**8/8

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